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(x−3)(x+3)2(x+3)=x−32the fraction with numerator open paren x minus 3 close paren open paren x plus 3 close paren and denominator 2 open paren x plus 3 close paren end-fraction equals the fraction with numerator x minus 3 and denominator 2 end-fraction ✅ The simplified expression is For access to the full range of exercises
ГДЗ по алгебре за 7 класс, решебник и ответы онлайн For access to the full range of exercises
yv=(2)2−4(2)+5=4−8+5=1y sub v equals open paren 2 close paren squared minus 4 open paren 2 close paren plus 5 equals 4 minus 8 plus 5 equals 1 ✅ Resources for Full Solutions (GDZ) For access to the full range of exercises
x2−92x+6the fraction with numerator x squared minus 9 and denominator 2 x plus 6 end-fraction Use the difference of squares formula